By Rakesh, Gupta

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Ordinate For a point lying on x-axis a. x co-ordinate = b. Y co-ordinate c. both co-ordinates are zeros d. none of these For a point lying on y-axis a. x co-ordinates = b. Y co-ordinate c. both co-ordinates are zeros d. none of these The point (2,4) lies in which quadrant? b. 2 nd c. 3 rd a. 1st The point (-3, 4) lies in which quadrant? a. 1st b. 2 nd c. 3rd The point (-3,-4) lies in which quadrant? b. 2 nd c. 3 rd a. 1st The point (7,-5) lies in which quadrant? l st . 3 rd ° ° d. Critical point = ° = ° d.

PQR = 0 or or or or or or Example 28 Solution 1(2a2t/ t 2-2a 2 tl t1) + (0-2a 2t 2) +(2a2 teO) I =0 2a2 tl t2 (~-t2) +2a2 (t1-t2) = 0 (1 +t1 t2) [tl +t2] = 0 either tl ~ + 1 = 0 or tet2 = 0 either tl t2 =-1 or ~ = t2 [ But tl * t2 given] tl ~ = -1 Which is the required condition. Find the value of A. ), (3,8) is 10 square units. the vertices of ~PQR. According to question, Area ~PQR = 10 2X 5 1 -7'Jf A. i. e. " 1(2A. ) + (15 -16) I = 10 or or I-A. -221 = 20 -A. :> A = -42 Taking -ve sign, -A -22 = -20 A =-2 A = -42 or-2 or ..

2,0) c. (0,2) d. (0,-2) N X' o X Y' /39/ 23. For what values of K the distance between the points (2,k) and a. 24. 3$ b. -$ c. J5) d. 2$ 25. The distance between (-l,a) and (5,5) is 10 unit, the value of a is a. -3 b. 13 c. both (a) and (b) d. 4 The points (6,1); (-2,1) and (2,-4) are the vertices of a triangle which is a. Isosceles b. Scalene c. Equilateral d. not form a triangle 26. j3,-1) and a. Isosceles b. Scalene d. J3,5) is 6 units are the vertices of a triangle which is c. Equilateral 27.